Sometimes the net force of an object is zero, this is when the forces are balanced. * 1 point True False

a) ¿En qué posición es mínima la magnitud de la fuerza sobre la masa de un sistema masa-resorte? 1) x 0, 2) x A o 3) x A. ¿Por q

Tatiana [17]

Answer:

a) the correct answer is 1 , b) x=0 F=0, a=0

x= 0.050 F= -7.5 N, a= -15 m/s²

x= 0.150 F= 22.5 N, a=- 45 m/s²

Explanation:

a) In a mass - spring system the force is given by the Hooke force,

F = - k x

Analyzing this equation we see that the outside is proportional to the elongation from the equilibrium position, therefore the force is zero when the spring is in its equilibrium position

the correct answer is 1

b) we assume that the given values are from the equilibrium position of the spring.

Let's calculate the force

x = 0

F = 0

x = 0.050

F = - 150 0.050

F = - 7.50 N

x = 0.150

F = - 150 0.150

F = - 22.5 N

let's use Newton's second law to find the acceleration

F = m a

a = F / m

x = 0 m

a = 0

x = 0.050 m

a = -7.50 / 0.50

a = - 15 m / s²

x = 0.150 m

a = - 22.5 / 0.50

a = - 45 m/s²

TRASLATE

a) En un sistema masa – resorte la fuerza es dada por la fuerza de Hoke,

F= - k x

analizando esta ecuación vemos que la fuera es proporcional a la elongación desde la posición de equilibrio, por lo tanto la fuerza es cero cuando el resorte esta en su posición de equilibrio

la respuesta correcta es 1

b)suponemos que los valores dados son desde la posición de equilibrio del resorte.

Calculemos la fuerza

x=0

F= 0

x=0.050

F = - 150 0.050

F= - 7.50 N

x= 0.150

F= - 150 0.150

F= - 22.5 N

usemos la segunda ley de Newton para encontrar la aceleración

F = m a

a = F/m

x =0 m

a = 0

x= 0.050 m

a = -7.50/ 0.50

a =- 15 m/s²

x= 0.150 m

a= - 22.5 / 0.50

a= - 45 m/s²

7 0

4 years ago

How is a ecosysten different from a community

Komok [63]

An ecosystem is the diversity of many communities of organisms where they interact with living as well as non living thing whereas community contains the variety of populations of different species. Hope this helps x

5 0

3 years ago

Read 2 more answers

A football quarterback runs 15.0 m straight down the playing field in 3.00 s. He is then hit and pushed 3.00 m straight backward

algol [13]

Answer:

a) $v_{1}=14.29m/s\\v_{2}=9.25m/s\\v_{3}=6.36m/s$

b) $v=+9.97m/s$

Explanation:

From the exercise we know that

$x_{1} =15m, t_{1}=3s$

$x_{2} =-3m, t_{1}=1.74s$

$x_{3} =29m, t_{3}=5.20s$

From dynamics we know that the formula for average velocity is:

$v=\frac{x_{2}-x_{1} }{t_{2}-x_{1} }$

a) For the three intervals:

$v_{1}=\frac{x_{2}-x_{1} }{t_{2}-t_{1} }=\frac{(-3-15)m}{(1.74-3)s}=14.29m/s$

$v_{2}=\frac{x_{3}-x_{2} }{t_{3}-t_{2} }=\frac{(29-(-3))m}{(5.20-1.74)s}=9.25m/s$

$v_{3}=\frac{x_{3}-x_{1} }{t_{3}-t_{1} }=\frac{(29-15)m}{(5.20-3)s}=6.36m/s$

b) The average velocity for the entire motion can be calculate by the following formula:

$v=\frac{v_{1}+v_{2}+v_{3} }{n} =\frac{(14.29+9.25+6.36)m/s}{3}=+9.97m/s$

8 0

3 years ago

A technician wraps wire around a tube of length 33 cm having a diameter of 8.1 cm. When the windings are evenly spread over the

inessss [21]

Explanation:

It is given that,

Length of the tube, l = 33 cm = 0.33 m

Diameter of the tube, d = 8.1 cm = 0.081 m

Number of turns, N = 590

(a) We need to find the self- inductance of the solenoid. The formula for the self inductance is given by :

$L=\dfrac{\mu_o N^2A}{l}$

A is the area of the solenoid

$L=\dfrac{4\pi \times 10^{-7}\times (590)^2\times \pi \times (0.0405)^2}{0.33}$

L = 0.00683 H

or

L = 6.83 mH

So, the self inductance of the solenoid is 6.83 mH.

(b) The current in this solenoid increases at the rate of 3 A/s. $\dfrac{dI}{dt}=3\ A/s$

EMF in the solenoid is given by :

$E=-L\dfrac{dI}{dt}$

$E=-6.83\times 3$

E = -20.49 volt

Hence, this is the required solution.

8 0

3 years ago

Explain what it means when we say that Earth’s oceans are in hydrostatic equilibrium. Now suppose you are a scuba diver. Would y

Mekhanik [1.2K]

Answer:

Explanation:

Hydrostatics put simply means fluids at rest (hydro-fluid, static-rest)

Oceans are basically bodies of fluid (water),

and as such they are in hydrostatic equilibrium or hydrostatic balance when they are at rest, or when the velocity of flow in them are constant over a given time. Hydrostatic equilibrium usually occurs when external forces acting on the ocean bodies balance each other out. An example is the force of gravity being balanced by a pressure-gradient force.

The pressure felt by a body in a fluid (water) is given by the formula P = ρgh

Where ρ is the density of the fluid

g is acceleration due to gravity

h is the depth of the body in the fluid.

ρg is constant for water and as a result the pressure you will feel in an ocean will depend on how far below the surface you are, h. The lower inside the water you are the higher the pressure you feel.

4 0

3 years ago