Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc
1 answer:
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Answer:
The voltage across the capacitor is 1.57 V.
Explanation:
Given that,
Number of turns = 10
Diameter = 1.0 cm
Resistance = 0.50 Ω
Capacitor = 1.0μ F
Magnetic field = 1.0 mT
We need to calculate the flux
Using formula of flux
Put the value into the formula
We need to calculate the induced emf
Using formula of induced emf
Put the value into the formula
Put the value of emf from ohm's law
We know that,
We need to calculate the voltage across the capacitor
Using formula of charge
Put the value into the formula
Hence, The voltage across the capacitor is 1.57 V.