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Verdich [7]
3 years ago
6

Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc

h as Jack's power output. four times Jack's power output. twice Jack's power output. one-half as much as Jack's power output. the same as Jack's power output.
Physics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

Second Choice.

Explanation:

Jack's Power = W/t

Jill's Power = 2W/(0.5)*t

2/0.5 = 4

Jill's Power = 4*W/t

Jill's Power is 4 times greater than Jack's

Second Choice

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Mary starts from her house, walks 80 meters south, and stops to chat with her aunt on the sidewalk. After chatting for a few min
maksim [4K]

Answer:

0.42 meters/second

Explanation:

The total distance traveled by Mary is: 80 m + 125 m + 45 m = 250 m  

We want the speed in meters/second, so we have to convert the 10 minutes elapsed during the trip into seconds. Then we need a conversion factor, 1 minute is equivalent to 60 seconds.

time = 10 minutes * (60 seconds/1 minute) = 600 seconds (notice that minute is cancelled because is multiplying and dividing)

Now, we can compute the average speed is as follows:

Average speed = total distance/time = 250 m/600 s =  0.42 m/s

6 0
4 years ago
in positive numbers less than 1, the zeros between the decimal point and non zero are _____ significant ​
Margaret [11]
Zeros the left of the decimal but still less than one are non significant but to the right they are.
For example: 0.003 (only 3 is significant) but for 0.030 (two are significant)
8 0
3 years ago
The bohr model of the atom addressed the problem of
cupoosta [38]
Rutherford's nuclear model stated that a cloud of negative electrons surround the nucleus however scientists realized that electrons in a cloud around the nucleus of an atom would be attracted to the nucleus, causing the atom to collapse. Thus Bohr's model proposed that electrons were contained in shells and they orbit the nucleus at fixed distances.
7 0
3 years ago
A billiard ball moving at 6.00 m/s strikes a stationary ball of the same mass. after the collision, the first ball moves at 5.39
kodGreya [7K]
<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision.  </span>

<span>After collision... </span>

<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>

<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component)  </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>

<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion.  </span>

<span>Hope you understand!</span>
5 0
4 years ago
Read 2 more answers
A sample of an ideal gas is heated, and its kelvin temperature doubles. What happens to the average speed of the molecules in th
BabaBlast [244]

A sample of an ideal gas is heated, and its kelvin temperature doubles. The average speed of the molecules in the sample will increases by a factor of  \sqrt{2}

The root-mean square (RMS) velocity is the value of the square root of the sum of the squares of the stacking velocity values divided by the number of values. The RMS velocity is that of a wave through sub-surface layers of different interval velocities along a specific ray path.

Root mean square speed is a statistical measurement of speed.

The root mean square speed can be calculated as : V1 : \sqrt{3 R T / Mo}

if  temperature becomes double

let T1 is initial temperature

So ,  T2 = 2 * T1

now ,

Root mean square speed will be (V2) =  \sqrt{(3 R (2T)) / Mo}

                                                     = \sqrt{2} * \sqrt{3 R T / Mo}

                                                     = \sqrt{2} V1

Thus when temperature becomes double, the root mean square speed increases by a factor of  \sqrt{2}

To learn more about root mean square velocity here

brainly.com/question/13751940

#SPJ4

3 0
1 year ago
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