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Vladimir [108]
3 years ago
13

Starting from rest, a car takes 2.4s to travel 15m. Assuming a constant acceleration, how long will it take the car to travel th

e next 15m?
Physics
1 answer:
Alborosie3 years ago
7 0

Answer:

T = 2.4 + 2.4 = 4.8 [s]

Explanation:

In order to solve this problem, we must use the following kinematics equation and calculate the acceleration value.

x=x_{o} +v_{o}*t+(\frac{1}{2})*a*t^{2}

Vo = inital velocity = 0

x - xo = 15 [m]

t = time = 2.4 [s]

15 = 0.5*a*(2.4)^2

a = 5.208 [m/s^2]

We can use the same equation to find the time.

30 = 15 + 0.5*(5.208)*t^2

t = 2.4 [s]

T = 2.4 + 2.4 = 4.8 [s]

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Two fishing boats depart a harbor at the same time, one traveling east, the other south. the eastbound boat travels at a speed 3
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2) After a time t=3~h, the two boats are 45~mi apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:
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The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which S_E and S_S are the two sides. Therefore, we can use Pythagorean theorem and write:
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