Differentiation is the process that creates specialized cells.
NADH and FADF2 are the reduced forms of the nicotinamide adenine dinucleotide (NAD) and flavin adenine dinucleotide (FAD) coenzymes.
<h3>What is nicotinamnde adenine dinucleotide?</h3>
The nicotinamnde adenine dinucleotide (NAD) is a coenzyme used in the transport electron chain of the cellular respiration.
The movement of electrons is coupled to a proton gradient in order to generate ATP, the energy coin of the cell.
In conclusion, NADH and FADF2 are the reduced forms of the nicotinamide adenine dinucleotide (NAD) and flavin adenine dinucleotide (FAD) coenzymes.
Learn more about NADH here:
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This statement is true.
In the case of autosomal dominant disease, the person is either homozygous (which is very rare) or heterozygous. On the molecular level, either the mutation produced a new deleterious protein for the organism, or the mutation affected an existing protein in the physiological state and that a 50% activity is not enough to compensate for the needs. of the body.
In case of autosomal recessive disease, the sick person is always homozygous. If the two loci each have a different mutant allele, it is called a "composite heterozygote". People with autosomal recessive inheritance disorder have "mandatory heterozygote" parents.
Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
