All categories

3 years ago

How do you solve this problem 3/2=x/324 i'm stuck

1 answer:

5 0

You have to find a common denominator. In this case it will be 486/324 = x/324. Then you would have to turn the 324 around. Then it will be 486/324 X 324. Which would be 486. Therefore. X = 486. Please tell me if I am wrong. Your welcome!

-Twix

You might be interested in

the smith family is designing new plans for an in ground pool. mr smith draws a rectangular shape with a length that is 5 feet l

Mnenie [13.5K]

Answer:
area of pool = w(w+5) = w^2 + 5w square feet

Explanation:
The height of the pool is used as its width.
Assume that the width of the pool is w feet.
Now, we are given that the length of the pool is 5 feet longer than its width.
This means that:
length of the pool = w + 5 feet
The area of the rectangle is calculated as follows:
area = length * width
area = (w+5) * (w)
area = w^2 + 5w square feet

Hope this helps :)

4 0

4 years ago

P(x) = 2x4 − x3 − 4x2 + 10x − 4

avanturin [10]

Answer: 2x ^4 +7x−4x ^2 −4

Step-by-step explanation:

2x ^4 −x*3−4x ^2 +10x−4

2x ^4 −3x−4x ^2 +10x−4

2x ^4 +(−3x+10x)−4x ^2 −4

2x ^4 +7x−4x ^2 −4

7 0

3 years ago

Can anyone help me solve this problem?

lions [1.4K]

Answer:

x=58, m<DCB=56°

Step-by-step explanation:

Ok the sum of those two angles should equal 180 degrees so,

2x+8+x-2=180

solve the equation

3x+6=180

3x=174

x= 58

M<DCB=x-2--> 58-2=56

6 0

3 years ago

Solve the system of linear equations by substitution.<br><br> −5x+3y=51<br> y=10x−8

DerKrebs [107]

I would do the work out but it’s a lot of work so heres a picture the work is already done.

3 0

2 years ago

Select the correct answer from each drop-down menu.

podryga [215]

Answer with explanation:

$\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}$

Average Height of tallest Building in San Francisco

$=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8$

Average Height of tallest Building in Los Angeles

$=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9$

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco

=233.9-197.8

=36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

|260-197.8|=62.2

|237-197.8|=39.2

|212-197.8|=14.2

|197 -197.8|= 0.8

|184 -197.8|=13.8

|183-197.8|=14.8

|183-197.8|= 14.8

|175-197.8|=22.8

|174-197.8|=23.8

|173 -197.8|=24.8

Average of these numbers

$=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12$

Mean absolute deviation=23.12

5 0

3 years ago