Since x can't be zero (it sits at the denominator of the left hand side), let's split cases:
If x is positive
It this case, we can multiply both sides by x without changing the inequality sign:
![\dfrac{1}{x} > x \iff 1 > x^2 \iff x \in (-1,1)](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7Bx%7D%20%3E%20x%20%5Ciff%201%20%3E%20x%5E2%20%5Ciff%20x%20%5Cin%20%28-1%2C1%29%20)
But since we're assuming that x is positive, we can only accept the numbers between 0 and 1.
If x is negative
It this case, in order to multiply both sides by x we have to change the inequality sign:
![\dfrac{1}{x} > x \iff 1 < x^2 \iff x \in (-\infty,-1) \cup (1,\infty)](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7Bx%7D%20%3E%20x%20%5Ciff%201%20%3C%20x%5E2%20%5Ciff%20x%20%5Cin%20%28-%5Cinfty%2C-1%29%20%5Ccup%20%281%2C%5Cinfty%29%20)
But since we're assuming that x is negative, we can only accept the numbers which are smaller than -1.
So, putting all the pieces together, we have that the solution is given by the following interval:
![(-\infty, -1) \cup (0,1)](https://tex.z-dn.net/?f=%20%28-%5Cinfty%2C%20-1%29%20%5Ccup%20%280%2C1%29%20)
Okay but there is no link attached
Answer:
Hey! I see you need some help, I gotchu.so heres what i got,
Medication A: 32 would be the main answer
Step-by-step explanation:
Week 1- even medication from A and medication B
Week2- Medication A: 80 milligrams Medication B: 48 milligrams
week 3- Medication A:? Medication B: 6
They seem to be reducing it by 42, so 48-42=6 (medication B)
So therefore, 80-42=32. would be for medication A
The y-intercept is 4 because it is the only number without a variable