<span>Which of the following is the solution set of the equation
10(x^2+1/x^20)-63(x-1/x)=52=0
I think you type wrongly the equation:
It is : </span><span>10(x^2+1/x^2)-63(x-1/x)+52=0
We know: x</span>²+1/x²=(x-1/x)²+2, pose x-1/x=t and we have x²+1/x²=t²+2
So 10(t²+2)-63t+52=0
or 10t²-63t+72=0
we have t=(63+33):20= 24/5
and t=(63-33):20=3/2
+ If t=3/2 we have x-1/x=3/2 or 2x²-3x-2=0 and we have x=2, x=-1/2
+ Of t=24/5 we have x-1/x=24/5 or 5x²-24x-5=0 or x=5 and x=-1/5
And the answer: <span>c) (5,2,-1/5,-1/2)</span>
Ans
B,D,F
Step-by-step explanation:
Y=5-x^2
Y=3x^2+1
Y=x^3
All you have to do is multiply 1,700,000 by .1 or you could divide 1,700,000 by 10 if you prefer that. The answer would be 170,000.
Given:
hamburger = h ; sells for 3
cheeseburger = c ; sells for 3.50
100 burger buns
h + c = 100
3h + 3.5c <u>></u> 80 last option.
