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olga55 [171]
3 years ago
10

Consider parallelogram WXYZ, where diagonal WY and XZ intersect at point Q. If WQ =8 and ZX = 20, which statement is true?

Mathematics
1 answer:
Alina [70]3 years ago
8 0

Answer:

C) YQ = 8

Step-by-step explanation:

If WQ is 8 and XZ bisects this line, this means that YQ is also 8.

If this answer is correct, please make me Brainliest!

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The sun of the first number and twice the second number is 16. The second number is two more than the first number. What are the
Bingel [31]

7+9=16

Step-by-step explanation:

let us add the numbers step by step:

Just add the numbers like this [1+3,2+4,3+5,4+6,5+7,6+8,7+9…]

you get the answer 7+9=16

7 0
3 years ago
If f'(x) is (x-4)(4-2x) , what is f(x)?
butalik [34]
We can apply some rules backwards

first
f'(x)=
(x-4)(-2x+4)
-2x^2+12x-16

we know that
f'(rx^n)=rnx^{n-1}
so therefor maybe
-2x^2=rnx^{n-1}
2=n-1
n=3
rn=-2
3r=-2
r=-2/3

one is
\frac{-2}{3}x^3
second part

12x
12x=rnx^{n-1}
x^1, 1=n-1
n=2
rn=12
2r=12
r=6
6x^2 is the second bit

last part
-16
-16x^0=rnx^{n-1}
0=n-1
n=1

rn=-16
1r=-16
r=-16

-16x^1

so therfor f(x)=\frac{-2}{3}x^3+6x^2-16x
3 0
3 years ago
Express 24 out of 80 as a percent
olga2289 [7]

Answer:

30%

Step-by-step explanation:

24/80 = 0.3

move the decimal over 2 times and you'll get your answer

6 0
3 years ago
A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
3 years ago
A chef buys 9cucumbers,18 peppers, and 21 tomatoes at the farmer's market. How much does she spend?
stepladder [879]
HAY THERE!

ACCORDING TO QUESTION:-
Cucumbers = 6 for $2
Peppers = 12 for $9
Tomatoes = 6 fir $4
____________
SO NOW
____________
\huge{SOLUTION:- }
____________
For 9 cucumbers = as 6 cucumbers is for $2 then 9 will be of $3........1️⃣

For 18 peppers = as 12 peppers are for$9 so 18 will be of $12.........2️⃣

For 21 tomatoes =as 6 tomatoes are for $4 then 21 tomatoes are $14 .......3️⃣

Now add 1️⃣ +2️⃣ + 3️⃣

here $3 +$12 + $14= $29

HOPE IT HELPED YOU.
6 0
3 years ago
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