7+9=16
Step-by-step explanation:
let us add the numbers step by step:
Just add the numbers like this [1+3,2+4,3+5,4+6,5+7,6+8,7+9…]
you get the answer 7+9=16
We can apply some rules backwards
first
f'(x)=
(x-4)(-2x+4)
-2x^2+12x-16
we know that

so therefor maybe
-2x^2=rnx^{n-1}
2=n-1
n=3
rn=-2
3r=-2
r=-2/3
one is

second part
12x
12x=

x^1, 1=n-1
n=2
rn=12
2r=12
r=6

is the second bit
last part
-16
-16x^0=

0=n-1
n=1
rn=-16
1r=-16
r=-16
-16x^1
so therfor f(x)=
Answer:
30%
Step-by-step explanation:
24/80 = 0.3
move the decimal over 2 times and you'll get your answer
At the start, the tank contains
(0.02 g/L) * (1000 L) = 20 g
of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.
Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of
(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s
In case it's unclear why this is the case:
The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.
So the amount of chlorine in the tank changes according to

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):


![\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B%5Cdfrac%7Bc%28t%29%7D%7B%28200-3t%29%5E%7B5%2F3%7D%7D%5Cright%5D%3D0)


There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

![\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}](https://tex.z-dn.net/?f=%5Cimplies%5Cboxed%7Bc%28t%29%3D%5Cdfrac1%7B200%7D%5Csqrt%5B3%5D%7B%5Cdfrac%7B%28200-3t%29%5E5%7D5%7D%7D)

ACCORDING TO QUESTION:-
Cucumbers = 6 for $2
Peppers = 12 for $9
Tomatoes = 6 fir $4
____________
SO NOW
____________

____________
For 9 cucumbers = as 6 cucumbers is for $2 then 9 will be of $3........1️⃣
For 18 peppers = as 12 peppers are for$9 so 18 will be of $12.........2️⃣
For 21 tomatoes =as 6 tomatoes are for $4 then 21 tomatoes are $14 .......3️⃣
Now add 1️⃣ +2️⃣ + 3️⃣
here $3 +$12 + $14= $29
HOPE IT HELPED YOU.