Ask question

Ask question

All categories

3 years ago

10

Calculate the change in temperature of 20 kg of water if 30 kg of aluminum is dropped in the water and the aluminum changes temp

erature by 20°C (Hint: use the principle of conservation of energy.) °C

1 answer:

vivado [14]3 years ago

6 0

<span>ΔE = 0

(m_alum) (c_alum) Δt - (m_water)(c_water) Δt' = 0

(30) (897) (20) - (20)(4186) Δt' = 0

Δt' = 6.42857 °C</span>

You might be interested in

An engine that has an efficiency of 25% takes in 200 [J] of heat during each cycle. Calculate the amount of work this engine per

BartSMP [9]

Answer:

$W=50J$

Explanation:

The work done $W$ and the energy taken $Q_{in}$ by a heat engine are related to the efficiency $\eta$ by the expression

$\eta=\frac{W}{Q_{in}}$

The efficiency is $\eta$ =25%, the numerical form of this percentage is 0.25 and the energy taken is $Q_{in}$ =200J. Replacing in the formula:

$0.25=\frac{W}{200}\\W=200*0.25\\W=50J$

5 0

2 years ago

spectroscope or a spectrometer is an instrument which is used for separating the components of light, which have different wavel

ohaa [14]

Answer:

The answer is B

Explanation:

The line spectrum shows distinct light different energies and wavelengths

7 0

2 years ago

Read 2 more answers

An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?

Norma-Jean [14]

Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s

6 0

2 years ago

The average power dissipated in a 47 ω resistor is 2.0 w. what is the peak value i 0 of the ac current in the resistor?

pishuonlain [190]

The average dissipated power in a resistor in a ac circuit is:
$P=I_{rms}^2 R$
where R is the resistance, and $I_{rms}$ is the root mean square current, defined as
$I_{rms} = \frac{I_0}{\sqrt{2}}$
where $I_0$ is the peak value of the current. Substituting the second formula into the first one, we find
$P=( \frac{I_0}{\sqrt{2} } )^2 R = \frac{1}{2} I_0^2 R$
and if we re-arrange this formula and use the data of the problem, we can find the value of the peak current I0:
$I_0 = \sqrt{ \frac{2 P}{R} }= \sqrt{ \frac{2 \cdot 2.0 W}{47 \Omega} }=0.29 A$

4 0

2 years ago

Plants are made of_________________cells, which have membrain-bound_____.

Readme [11.4K]

Plant cells are eukaryotic cells that differ in several key aspects from the cells of other eukaryotic organisms. number two sry but Idk
:(

4 0

3 years ago