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natka813 [3]
3 years ago
6

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.15 m/s . Her husband Bruce suddenly reali

zes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 44.4 m above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 8.00 s after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance.
Required:
a. With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground?
b. Where is Henrietta when she catches the bagels?

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

a 15.22 m/s

b 45.65 m

Explanation:

Using the same formula,

x = vt, where

x is now 45.65, and

t is 3 s, then

45.65 = 3v

v = 45.65/3

v = 15.22 m/s

See the attachment for the part b. We used the distance gotten in part B, to find question A

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An open pipe on an organ creates
PilotLPTM [1.2K]

Answer: 0.0163

Explanation: fn=n x v/2L

Fundamental frequency =f1

1 x (343/2L) = 10500

Rearrange the equation

L= v/(2xFn)

L= 343/(2x10500)

L=0.0163

8 0
2 years ago
An electron in a hydrogen atom is in a p state. Which of the following statements is true?
zhenek [66]

Answer:

The electron’s wavefunction has at least one node (i.e., at least one place in space where it goes to zero).

Explanation:

We know that the p-orbitals have nodes. A node is a region where the probability of finding an electron goes down to zero.

P orbitals are oriented along the x,y,z Cartesian axes and are known to have angular nodes along the axes.

Hence, if an electron in a hydrogen atom is in a p state, the electron’s wavefunction has at least one node

6 0
3 years ago
HELP PLS! :/
zlopas [31]

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 0
2 years ago
80 POINT!!!!! IT'S WORTH IT!!!!!
alexandr402 [8]

because blah blah blah blah

3 0
2 years ago
At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the
krok68 [10]

Answer:

s₁ = 240,000 km

Explanation:

The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,

s = s₁ + s₂

where,

s = total distance between the focuses = ?

s₁ = distance between f1 and moon = 200,000 km

s₂ = distance between f₂ and moon = 300,000 km

Therefore,

s = 200,000 km + 300,000 km

s = 500,000 km

Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:

s = s₁ + s₂

500,000 km = s₁ + 260,000 km

s₁ = 500,000 km - 260,000 km

<u>s₁ = 240,000 km</u>

5 0
3 years ago
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