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2 years ago

10

An object has an acceleration of 12.0m/s/s. If the mass of this object were doubled (with no change in its net force), then it’s

new acceleration would be ___ m/s/s.

1 answer:

VladimirAG [237]2 years ago

8 0

Answer:

6m/s^2

Explanation: this is because when the object is mass is increasing the object's acceleration will divide into two.

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Two parallel plates of area 2.34*10-3 M2 have 7.07*10-7C of charge placed on them. A6.62*10-5C charge q1 is placed between the p

ira [324]

Answer:

The force exerted on the $q_1$ is $F = 2.25*10^{3} \ N$

Explanation:

From the question we are told that

The area is $A = 2.34*10^{-3} \ m^2$

The magnitude of charge placed on them is $q = 7.07 * 10^{-7} C$

The charge placed between the plate is $q_1 = 6.62 *10^{-5} C$

The electric field generated around the plate is mathematically represented as

$E = \frac{q}{A \epsilon_o}$

Substituting values

$E = \frac{7.07*10^{-7}}{2.34*10^{-3} * 8.85 *10^{-12}}$

$E = 34*10^{6} \ V/m$

The force exerted the charge $q_1$ is mathematically represented as

$F = q_1 * E$

Substituting values

$F = 6.62 *10^{-5} * 34*10^{6}$

$F = 2.25*10^{3} \ N$

8 0

3 years ago

A boat moves with a speed of +2.5 m/s in a direction 25° north of east. If the mass of the boat is 15,000 kg, what is the moment

nadya68 [22]

Momentum - mass in motion
P=MV
P=(15,000 kg)(2.5 m/s)
P=37 500 kg x m/s to the north
Hope this helps

5 0

3 years ago

(c) What would the angle of reflection be if the incident ray

kvasek [131]

Answer:

So, if a wave hits a mirror at an angle of 36°, it will be reflected at the same angle (36°). ... An incident ray of light hits a plane mirror at an angle and is reflected back off it. The angle of reflection is equal to the angle of incidence. Both angles are measured from the normal.

Explanation:

3 0

3 years ago

An 85.0 kg fisherman jumps from a dock at a speed of 4.30 m/s onto their 135.0 kg boat. If the boat was at rest to begin but mov

jeka94

Answer:

Final speed of boat + man is 1.66 m/s

Explanation:

As we know that there is no friction on the system or there is no external force on this system

So here we can use momentum conservation here

$mv = (m + M)v_f$

so we have

m = 85 kg

M = 135 kg

v = 4.30 m/s

now we have

$85 \times 4.30 = (85 + 135) v$

$v = 1.66 m/s$

4 0

3 years ago

What kind of deformation does a cube of Jell-O exhibit when it jiggles?

nadya68 [22]

It depends on chemistry... A physical deformation to the Jell-O.

3 0

4 years ago