Question

A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 45 m/s, and the average southward velocity has a magnitude of 37 m/s. Taking northward to be the positive direction, what is the average velocity for the trip?

Answer 1

Answer:

v = 24.5 m

Explanation:

Average speed is defined as

       v = ($x_{f}$ - x₀) / t

The distance is

        x = v t

In this case we can find the speed

       v = (v_nort ¾ t + v_sud ¼ t) / t

        v = 45 ¾ - 37 ¼

        v = 24.5 m