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timurjin [86]
3 years ago
15

Suppose you are taking the bus home, and can take either the 51 or the 82. you know that the 82 will arrive in exactly 10 minute

s, but because the 51 is unreliable, you suspect that the amount of time until it arrives is uniformly distributed between 0 and 30 minutes. you take the first bus that arrives. let t be the number of minutes you wait until you board a bus. find e[t].
Mathematics
1 answer:
elena55 [62]3 years ago
8 0
We are dealing here with a uniform distribution ranging from 0 to 30 minutes.  We need to calculate the probability that the unreliable bus will arrive before the reliable one.  This probability is the area under the uniform distribution "curve" from 0 to 10 minutes.  This constitutes 1/3 of the entire unform distr. curve.  So the probability that the unreliable bus will arrive before the reliable one is 1/3, or 0.33.  The probability that it will arrive AFTER the reliable bus is 2/3, or 0.67.
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quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

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Step-by-step explanation:

5 0
3 years ago
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Answer:

A/15=5

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therefore a=75

Step-by-step explanation:

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