Question

What is the equation of the line in slope intercept form through (-5,-3) and (6,1) ?

Answer 1

y - y1 = m (x - x1)

where m is the slope and (x1 , y1) is the point given

m = (y2-y1)\(x2-x1)

we have  (-5,-3) and (6,1)

so: m = (1- -3) / (6- -5) = (1+3)/(6+5) = 4/11

and the equation of the line is:
y - y1 = m (x - x1)
y-1 = 4/11 (x-6)

simplify:

y = 4/11 x - 24/11 +1

$y= \frac{4}{11} x - \frac{13}{11}$

I hope that helps!