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Helga [31]
3 years ago
12

What is the equation of the line in slope intercept form through (-5,-3) and (6,1) ?

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0

y - y1 = m (x - x1)

where m is the slope and (x1 , y1) is the point given

m = (y2-y1)\(x2-x1)

we have  <span>(-5,-3) and (6,1)

so: m = (1- -3) / (6- -5) = (1+3)/(6+5) = 4/11

and the equation of the line is:
</span>y - y1 = m (x - x1)
y-1 = 4/11 (x-6)

simplify:

y = 4/11 x - 24/11 +1

y= \frac{4}{11} x -  \frac{13}{11}

I hope that helps!



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d.<span>Since desk does not budge, </span><span>frictional force = Fx
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<span>                                                 Normal force </span><span>= 50 * g - Fy
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</span>____________________________________________________________
6)<span> Let F_net = 0</span>
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b. The equation that describes the forces which act in the y-direction:
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c. The values of friction and normal forces will be:
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The Normal force is not 490N in either case...
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r^3 = \dfrac{3V}{4 \pi}

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2 years ago
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brainly.com/question/1475130

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       =2,-5/2

6 0
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