Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation:
Answer:
aw baby naw that not cool
Step-by-step explanation:
Answer:
The answers are 40 : 1 and 16 : 5
Step-by-step explanation:
3. ) 400 : 10
Cancel out two of the zeros to get-
40 : 1
6. ) 1600m : 5km
1 km = 100 m, Therefore-
1600 : 500
Cancel out the zeros to get-
16 : 5
Answer:
the answer is 44
Step-by-step explanation:
4*2=8
48-(32:8)
48-(4)
44
I really hope it helps:))))))))))
7 + 10/2
7 + 5
12 is the answer to the problem
