In a litter of five puppies, what is the probability of getting
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y - y₁ = m(x - x₁)
y - (-4) = 1(x - 8)
y + 4 = 1(x) - 1(8)
y + 4 = x - 8
- 4 - 4
y = x - 12
y - y₁ = m(x - x₁)
y - (-4) = 1(x - 8)
y + 4 = 1(x) - 1(8)
y + 4 = x - 8
- 4 - 4
y = x - 12
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