Answer:
D, you simply just add 1.3 each time.
Answer;
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Step-by-step explanation:
The complete question is as follows;
For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05
Solution is as follows;
Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.
Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Answer:
4
Step-by-step explanation:
;)
Answer:
Step-by-step explanation:
The function approaches its horizontal asymptote in both directions as the magnitude of x gets large. The limit is y = 1.
Answer:
720
Step-by-step explanation:
For the first wedge, you have 6 numbers to choose from .
For the second wedge , you have 5 numbers to choose from .
For the 3rd wedge , you have 4 numbers to choose from .
For the 4th wedge , you have 3 numbers to choose from .
For the 5th wedge , you have 2 numbers to choose from .
For the 6th wedge , you have 1 number to choose from .
Conclusion: this numbering can be done in:
6×5×4×3×2×1 = 720
Note :
Generally ,we write 6×5×4×3×2×1 as 6! and we read it 6 factorial.
