Lateral surface area of the prism = 920 in²
Total surface area of the prism = 1180 in²
Solution:
Length of the prism = 13 in
Width of the prism = 10 in
Height of the prism = 20 in
Lateral surface area of the prism = 2(l + w)h
= 2(13 + 10) × 20
= 2(23) × 20
= 920 in²
Lateral surface area of the prism = 920 in²
Total surface area of the prism = Lateral area + 2lw
= 920 + 2 × 13 × 10
= 920 + 260
Total surface area of the prism = 1180 in²
Hence Lateral surface area of the prism = 920 in²
Total surface area of the prism = 1180 in²
6+3n≤40
Use inverse operations i.e.
4x+2<10
-2 -2
4x<8
4*x/4<8/4
x<2
Answer:
16
Step-by-step explanation:
I dont really inderstand but i would say 16 because it is closer to adding up to 43 so yea
Answer:
∠ WZX = 50°
XW is not an altitude.
Step-by-step explanation:
16. See the attached figure.
XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ
Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13
Hence, ∠ YXZ = 2 ∠ WXY
⇒ 8x + 34 = 2(10x - 13)
⇒ 8x + 34 = 20x - 26
⇒ 12x = 60
⇒ x = 5.
Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)
Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°
Hence, from Δ WXZ,
∠ WZX + ∠ WXZ + ∠ XWZ = 180°
⇒ 50° + 37° + ∠ XWZ = 180°
⇒ ∠ XWZ = 93° ≠ 90°
Hence, XW is not an altitude. (Answer)
Answer:
17
Step-by-step explanation:
-(-17)= 17