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Feliz [49]
3 years ago
11

Evita buys seed packets for the neighborhood vegetable garden. One packet of tomato seeds costs $3. One packet of radish seeds c

osts $4. Let t represent the number of packets of tomato seeds and r represent the number of packets of radish seeds. Evita spent $31 on 9 seed packets. How many packets of radish seeds did she buy? Use the table to guess and check.
Mathematics
2 answers:
zysi [14]3 years ago
8 0

No table is provided.

"Guess and check" is a solution method suitable for multiple choice questions and other questions that don't have a simple and obvious method for obtaining a solution directly.

For problems of this sort, you can usually work them in your head by assuming all of the total comes from the least contributor. Here, that would be tomato packets at $3 each. Buying 9 packets will result in a total of $27, which is $4 short of the actual total. Now, consider how much more the radish packets are. they are $4 - $3 = $1 more for each packet. That is, the $4 shortfall in total cost can be made up by having four (4) radish packets in the mix.

Without "guess and check" you have found that Evita bought 4 packets of radish seeds.

_____

I suppose you could "guess and check" using ...

9 tomato + 0 radish : 9*$3 + $0 = $27

8 tomato + 1 radish : 8*$3 + 1*$4 = $28 . . . . up by $1. We need to go up 3 more

5 tomato + 4 radish : 5*$3 + 4*$4 = $31 . . . . the solution we want

DanielleElmas [232]3 years ago
7 0

Answer:

btw the answer is 4

Step-by-step explanation:

i took the test

HOPE THIS HELPS!!!

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2 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
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oksian1 [2.3K]
The answer 749.6 is the answer
6 0
3 years ago
OK SO HERES THE PROBLEM. MY BRAIN HURTS. PLZZZ help me with this math problem
jeka57 [31]

Oh Foxy, Foxy, how totally debilitated you must be !  Try to relax.  Nobody
enjoys a painful brain, and believe me, this problem is not worth it.

Let me put it to you this way:  What if the problem said . . .

-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?

If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .

That's <em>almost </em>exactly what the problem <em>does</em> say. 
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.

Surely you can handle it from here, even with half of your brain
tied behind your back.

Take a good hard look at ' A ', and then go lie down.


7 0
3 years ago
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