Question

The edges of the diameter of a circle are at (-1,2) and (3,-1). Write the equation of the circle in general form.

Answer 1

Answer:

(x-1)²+ (y-0.5)²=6.25

Step-by-step explanation:

The standard form of equation of a circle is;

(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius

Finding the mid-point of the given points

(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)

midpoint= {1/2(-1+3), 1/2(2+-1)}

midpoint=(1,0.5)

Finding the radius r; the distance from the center to either of the given two points

Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²

Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then

d=√ (-1-1)² +(2-0.5)²

d= √ (-2)²+(1.5)²

d=√4+2.25⇒√6.25⇒2.5

r=2.5

Equation of the circle

(x-1)² + (y-0.5)²=2.5²

(x-1)²+ (y-0.5)²=6.25