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Zarrin [17]
2 years ago
14

Jose bought 750 bags of peanuts for $375.00. He intends to sell each bag for $0.15 more than he paid. How much should he charge

for each bag?
$0.35
$0.50
$0.55
$0.65

Mathematics
1 answer:
svet-max [94.6K]2 years ago
6 0
Answer: $0.65

Explanation: First find how much Jose paid for each bag
$375 / 750
So $0.50 per bag

Now add $0.15 to that
$0.50 + $0.15

That added together is
$0.65
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A plane is approaching an aircraft carrier at 25° angle of elevation from 3.2 miles away how far above sea level is the plane
s2008m [1.1K]

Answer:

Height\approx 1.35\ miles

Step-by-step explanation:

The angle of elevation=25\textdegree

It is 3.2\ miles away from the point.

If we imagine a right  triangle having an angle 25\textdegree.

Hypotenuse=3.2, Opposite=Height from sea level(h)

\sin 25=\frac{opposite}{hypotenuse}\\\\\sin 25=\frac{h}{3.2}\\\\h=3.2\times \sin 25\\\\h=3.2\times 0.4226\\\\h=1.3524\approx 1.35\ miles

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3 years ago
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GarryVolchara [31]

Answer:

abt 8.77

Step-by-step explanation:

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Miss smith’s pay is directly proportional to the number of hours she work at the airport. Her pay for 22 hours is $297.How much
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Answer:

$540

Step-by-step explanation:

You need first to calculate the hour rate that is payment divided to total number of hours done.

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3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

Operating on the right side:

\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

Solving for h:

\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

h = 61.5 m

The building is 61.5 m tall

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Answer:

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