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xxMikexx [17]
2 years ago
15

Can someone help me with this problem?

Mathematics
1 answer:
Anestetic [448]2 years ago
4 0
Answer: I don't know





Step-by-step explanation: Jk, the answer is X = 3 or 1/3
/ = Fraction
^ = Power-of
* = Multiply
Move all the terms to the left then multiply the parentheses:
(5x+3) (10-2) - (7x) * (8x) = 0
(50x^2-10x+30x-6)-7x*88x
Then multiply variables:
(50x^2-10x+30x-6)-56x^=0
Now add all the numbers together:
6x^2+20x-6=0
= 256x
Use the following formula:
x1=−b−Δ√2a
x2=−b+Δ√2a
Set up the problem:
√ =√256=16
Part 1: -20-16/2x-6 = -36/-12 = 3
Part 2: -20+16/2x-6 = -4/-12 = 1/3

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Which of the following is not a way to represent the solution of the inequality 8x - (5x + 4) greater than or equal to -31?
n200080 [17]
The response is 
<span>x greater than or equal to -9
</span>proof
8x - (5x + 4)>= -31, 3x- 4>= -31, 3x >= -27,  <span>x>= -27/3= -9
so </span><span>x greater than or equal to -9</span>
5 0
3 years ago
Read 2 more answers
If f(1) = 160 and f(n+ 1) = -2f(n), what is f(4)?
sertanlavr [38]
F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320

Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640

Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280

Final Answer: -1280

7 0
3 years ago
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Solve 3x 2 + 11x + 6 = 0
ollegr [7]

Answer:

x=

3

2

​

=0.667

x=3

Step-by-step explanation:

6 0
3 years ago
A quadratic function f is given <br> F(x)= x^2_4x+6 <br> Express f in standard form ?
Dennis_Churaev [7]

Hey there!

In the equation mentioned,

f represents function.

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7 0
3 years ago
What is AE?<br> Enter your answer in the box?
Nataly [62]

Answer:

AE = 18 units

Step-by-step explanation:

Δ AEB and Δ DEC are similar , then corresponding sides are in proportion, that is

\frac{AE}{DE} = \frac{AB}{DC} , substitute values

\frac{2x+4}{x+8} = \frac{12}{10} ( cross- multiply )

10(2x + 4) = 12(x + 8) ← distribute parenthesis on both sides

20x + 40 = 12x + 96 ( subtract 12x from both sides )

8x + 40 = 96 ( subtract 40 from both sides )

8x = 56 ( divide both sides by 8 )

x = 7

Then

AE = 2x + 4 = 2(7) + 4 = 14 + 4 = 18 units

5 0
3 years ago
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