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2 years ago

Can someone help me with this problem?

Mathematics

1 answer:

Anestetic [448]2 years ago

4 0

Answer: I don't know

Step-by-step explanation: Jk, the answer is X = 3 or 1/3
/ = Fraction
^ = Power-of
* = Multiply
Move all the terms to the left then multiply the parentheses:
(5x+3) (10-2) - (7x) * (8x) = 0
(50x^2-10x+30x-6)-7x*88x
Then multiply variables:
(50x^2-10x+30x-6)-56x^=0
Now add all the numbers together:
6x^2+20x-6=0
= 256x
Use the following formula:
x1=−b−Δ√2a
x2=−b+Δ√2a
Set up the problem:
√ =√256=16
Part 1: -20-16/2x-6 = -36/-12 = 3
Part 2: -20+16/2x-6 = -4/-12 = 1/3

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

A chemist mixes 175 millilters of solution that is 62% acid with 75 milliliters of pure acid. What percentage of the resulting M

Anton [14]

Answer:

73.4%

Step-by-step explanation:

The ratio of acid to mixture volume is ...

(0.62·175 +1.00·75)/(175 +75) = 183.5/250 = 0.734 = 73.4%

73.4% of the resulting mixture is acid.

3 0

3 years ago

"Expand the brackets and Simplify"<br>(pls i need help asap)

givi [52]

A) 2(1+2c)

2+4c = 2+4c

B) 6(14r-2t)

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2 years ago

Sylvester wants his hand to have a sum of -1. Click on three cards that Sylvester could choose. . -9 , 5 , -7, 1 , 4 , -2 , 3

irina1246 [14]

5,3 and -9 equal -1..

8 0

3 years ago

Ik the answer but can you explain how <br> Giving brainliest

natka813 [3]

Answer:

4/5 * 3/7

To multiply the fractions, multiply the numerators and denominators separately

4*3/5*7

multiply the numbers

12/5*7

multiply the numbers

12/35

hope that helps

Step-by-step explanation:

8 0

2 years ago

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