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Bess [88]
3 years ago
5

HELP PLEASE WITH 5 QUESTIONS!!!

Mathematics
1 answer:
Lorico [155]3 years ago
7 0
C) 1.94
A) 35%
A) 200%
A) 270
A) 252
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Daniela is a stain glass artist; she created the window below for her living room. What is
OLga [1]
The window has a shape of a semi-circle (half of a circle).

We know the diameter d = 12 ft.

The area of a (complete) circle is given by the formula:
A = π × r²

The radius can be found by halving the diameter:
r = d ÷ 2
  = 12 ÷ 2
  = 6 ft

Therefore the area of the circle will be:
<span>A = π × r²
    = 3.14 × 6</span>²
    = <span>3.14 × 36
    = 113.04 ft²

And the area of the semi-circle:
A = </span><span>113.04 </span>÷ 2
   = 56.52 ft²

Hence, the area of the window will be 56.52 ft².
3 0
3 years ago
Find the length of AB given that DB is a median of the triangle AC is 46
slava [35]

ANSWER:

The value of AB is 23

STEP-BY-STEP EXPLANATION:

We know that AB is part of AC, and that DB cuts into two equal parts (half) since it is a median, therefore the value of AB would be

\begin{gathered} AB=\frac{AC}{2} \\ AB=\frac{46}{2} \\ AB=23 \end{gathered}

6 0
1 year ago
Landon invested $110 in an account paying an interest rate of 4.1% compounded
krok68 [10]

Answer:

the amount after 5 years using compound continuously is $135.03

Step-by-step explanation:

The computation of the amount after 5 years using compound continuously is as follows

= Principal × e^(rate × time period)

= $110 × e^(4.2% × 5)

= $110 × 1.227525065

= $135.03

Hence, the amount after 5 years using compound continuously is $135.03

We simply applied the above formula so that the correct value could come

And, the same is to be considered  

7 0
2 years ago
Find the value of 17C3 <br> 680<br> 12,376<br> 2,380<br> 54
trapecia [35]

Answer:

54 because I don't know I can't explain

7 0
2 years ago
Read 2 more answers
Using sum or difference formulas, find the exact value of sin(165∘)
Nikitich [7]
\bf \textit{Sum and Difference Identities}&#10;\\ \quad \\&#10;sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})&#10;\\ \quad \\&#10;sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})\\\\&#10;-------------------------------\\\\

\bf sin(165^o)\implies sin(120^o+45^o)&#10;\\\\\\&#10;sin(120^o)cos(45^o)~+~cos(120^o)sin(45^o)\implies \cfrac{\sqrt{3}}{2}\cdot \cfrac{\sqrt{2}}{2}~+~\cfrac{-1}{2}\cdot \cfrac{\sqrt{2}}{2}&#10;\\\\\\&#10;\cfrac{\sqrt{6}}{4}~-~\cfrac{\sqrt{2}}{4}\implies \cfrac{\sqrt{6}-\sqrt{2}}{4}
6 0
3 years ago
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