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Fofino [41]
2 years ago
13

Formula1" title=" {y}^{2} + \frac{3y}{2} = \frac{27}{2} " alt=" {y}^{2} + \frac{3y}{2} = \frac{27}{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
5 0
Answer: 3, - 9/2
Explain
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Last option is none of the above
BigorU [14]

Answer:

A and B

Step-by-step explanation:

When rotating a point (or any shape around a certain point), none of the diameters of the shape will change. So for example, with this circle, when you rotate it around a point, the radius and circumference will not change because it has just rotated. It wont be on the x-axis though because point P is not on the x-axis an it is being rotated 180 degrees about point P. Just know that when you are rotating, nothing about the shape changes, all angles or measurements will be the same, it is just moving to a different place.

Hope this helped ^-^

7 0
3 years ago
Why do you divide each term in the sum by the same factor that you pull out of the sum?
arsen [322]

We do so to follow the rule of divisibility of each term(numbers).

<h2 /><h3><u>The Rule of Divisibility:</u></h3>

The rule of divisibility of numbers is a method applied in mathematics used to determine if a number or set of numbers is divisible by a particular integer without any remainder.

Let assume that we have a series of numbers;

  • 2, 4, 6, 8, 10

From the rule of divisibility, since all the numbers are multiples of 2;

We can deduce that 2 can be the factor that is pulled out from the series to divide each term in the sum.

Learn more about the rule of divisibility here:

brainly.com/question/840412

5 0
2 years ago
WILL GIVE BRAINLIEST
Katena32 [7]

Answer:

it's the point T.

Hope it helps

3 0
3 years ago
Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

5 0
2 years ago
The 5 in 6.052 has 1/10 the value of the 5 in ? Please explain
zepelin [54]
The tenths place, starting from the right, it gets higher going to the left. so the tenths place is only ten times greater than it.
6 0
3 years ago
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