<img src="https://tex.z-dn.net/?f=%20%7By%7D%5E%7B2%7D%20%2B%20%5Cfrac%7B3y%7D%7B2%7D%20%3D%20%5Cfrac%7B27%7D%7B2%7D%20" id="Tex

first u look where the first long arrow goes on this problem then you follow the second arrow which stops at 6 then u count how much until negative 2. but how I did it is the form 14 how much to 0 which is 14 the I count how many until I get to -2 and there's the answer

3 0

2 years ago

W(1,8),X(7,8),Y(4,5), and Z(1,2) select all methods you can use to prove WYZ is congruent to WYX

marin [14]

The distance between two points (x₁,y1),(x₂,y₂) is d
$d= \sqrt{(x2-x1)^2 + (y2-y1)^2}$

For the given problem we have
W(1,8),X(7,8),Y(4,5), and Z(1,2)

The length of WY = $\sqrt{(4-1)^2 + (5-8)^2}$ = 3√2
The length of WX = $\sqrt{(7-1)^2 + (8-8)^2}$ = 6
The length of WZ = $\sqrt{(1-1)^2 + (2-8)^2}$ = 6
The length of XY = $\sqrt{(4-7)^2 + (5-8)^2}$ = 3√2
The length of ZY = $\sqrt{(1-4)^2 + (2-5)^2}$ = 3√2

∴ WX = WZ ⇒⇒⇒ proved
XY = ZY ⇒⇒⇒ proved
WY = WY ⇒⇒⇒ reflexive property

∴ ΔWYZ is congruent to ΔWYX by SSS method

5 0

2 years ago