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Umnica [9.8K]
3 years ago
14

Find each measure Please help me

Mathematics
2 answers:
Kruka [31]3 years ago
3 0

Answer:

1. m∠CGB=120

3. m∠AGD=90

5. m∠CGD=150

2. m∠BGE=60

4. m∠DGE=30

6. m∠AGE=120

Step-by-step explanation:

Sorry that they are out of order.

den301095 [7]3 years ago
3 0

Answer:

1. m∠CGB=120°

2.m∠BGE=60°

3.m∠AGD=90°

4.m∠DGE=30°

5.m∠CGD=150°

6.m∠AGE=120°

Step-by-step explanation:

My work is scatterbrained so I'm not gonna be any help if I give an explanation.

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A digit is written to the right of the units digit of 757. If the resulting four-digit number is divisible by 3, how many possib
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3

Step-by-step explanation:

It is a well known trick that when you add together the digits of a number, if they are a multiple of 3 then the number is divisible by 3. Let's go through the options and check them:

7+5+7+0=19 not a multiple of 3

7+5+7+1=20 not a multiple of 3

7+5+7+2=21 multiple of 3

7+5+7+3=22 not a multiple of 3

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7+5+7+5=24 multiple of 3

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4 0
3 years ago
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

⇒ S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})

All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

4 0
3 years ago
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