Can you put up a picture of the rectangle
Answer:
3
Step-by-step explanation:
It is a well known trick that when you add together the digits of a number, if they are a multiple of 3 then the number is divisible by 3. Let's go through the options and check them:
7+5+7+0=19 not a multiple of 3
7+5+7+1=20 not a multiple of 3
7+5+7+2=21 multiple of 3
7+5+7+3=22 not a multiple of 3
7+5+7+4=23 not a multiple of 3
7+5+7+5=24 multiple of 3
7+5+7+6=25 not a multiple of 3
7+5+7+7=26 not a multiple of 3
7+5+7+8=27 multiple of 3
7+5+7+9=28 not a multiple of 3
As you can see, only 3 of these were possibilities that satisified the conditions. Hope this helps!
Answer:
; 5
Step-by-step explanation:
Given series :
Sum of series = ![S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]](https://tex.z-dn.net/?f=S_n%3D%5Csum%5E%7B%5Cinfty%7D_%7B1%7D%5C%20%5B%5Cdfrac%7B5%7D%7Bn%5Ccdot%28n%2B1%29%7D%5D%3D5%5B%5Csum%5E%7B%5Cinfty%7D_%7B1%7D%5Cdfrac%7B1%7D%7Bn%5Ccdot%28n%2B1%29%7D%5D)
Consider 

⇒ ![S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]](https://tex.z-dn.net/?f=S_n%3D5%5Csum%5E%7B%5Cinfty%7D_%7B1%7D%5Cdfrac%7B1%7D%7Bn%5Ccdot%28n%2B1%29%7D%3D5%5Csum%5E%7B%5Cinfty%7D_%7B1%7D%5B%5Cdfrac%7B1%7D%7Bn%7D-%5Cdfrac%7B1%7D%7Bn%2B1%7D%5D)
Put values of n= 1,2,3,4,5,.....n
⇒ 
All terms get cancel but First and last terms left behind.
⇒ 
Formula for the nth partial sum of the series :

Also, 
