Solve for x over the real numbers:
x^2 - 4 x = 5
Subtract 5 from both sides:
x^2 - 4 x - 5 = 0
x = (4 ± sqrt((-4)^2 - 4 (-5)))/2 = (4 ± sqrt(16 + 20))/2 = (4 ± sqrt(36))/2:
x = (4 + sqrt(36))/2 or x = (4 - sqrt(36))/2
sqrt(36) = sqrt(4×9) = sqrt(2^2×3^2) = 2×3 = 6:
x = (4 + 6)/2 or x = (4 - 6)/2
(4 + 6)/2 = 10/2 = 5:
x = 5 or x = (4 - 6)/2
(4 - 6)/2 = -2/2 = -1:
Answer: x = 5 or x = -1
Answer:
(-3,0)
Step-by-step explanation:
So first we wanna find how for the x value is on point a to point b and how far the y value is from point a to point b. the x on point a is 9 units away from point b and y is 18 units away. Then we find out what 2/3s of 9 and 18 is which would be 6 and 12. So then we take the A coordinates (9,-6) and subtract 12 from the x value and 6 from the y value to get the new coordinates of (-3,0)
Answer:
X11 = 300
Step-by-step explanation:
X11 = 10 × 3(11 - 1)
X11 = 10 × 3(10)
X11 = 10 × 30
X11 = 300
Answer:
bro whats the question
Step-by-step explanation:
Answer: 61.16 ft
Step-by-step explanation:
We can think in this situation as a triangle rectangle.
where:
The height of the tree is one cathetus
The shadow of the tree is the other cathetus.
We know that the angle of elevation of the sun is 78°, an angle of elevation is measured from the ground, then the adjacent cathetus to this angle is the shadow of the tree. And the opposite cathetus will be the height of the tree.
Now we can remember the relationship:
Tg(A) = (opposite cathetus)/(adjacent cathetus)
Where:
A = 78°
Adjacent cathetus = 13ft
opposite cathetus = height of the tree = H
Then we have the equation:
Tg(78°) = H/13ft
Tg(78°)*13ft = H = 61.16 ft