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3 years ago

<ABD has a measure of 36 degrees. a)find the compliment of the angle b)find the supplement of that angle

1 answer:

6 0

A) The complement of an angle is the other angle that can be added to the original to add up to 90 degrees. The complement of <ABD would be 90-36=54

b) The supplement of an angle is whatever number can be added to the original to add up to 180 degrees. The supplement of <ABD would be 180-36=144

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What is 694 divided by 41 and what is the remainder please help thank you

Studentka2010 [4]

16... Remainder of 38

41 x 16 = 656 therefore 38 left over

4 0

3 years ago

Read 2 more answers

Maria's family has a maple tree and a pine tree in their front yard. The maple tree is 6

ki77a [65]

Answer:

Pine tree is 42 feet tall

Step-by-step explanation:

Since Maple tree is shorter than pine tree, you add 6 to 36 which is 42.

42 Feet

5 0

3 years ago

Drop and Drag A)reflection (in x) B)reflection (in y) C)rotation D)translation

djyliett [7]

Answer:

Step-by-step explanation:

because y is a rotation that rotates up and down like a ramp!

4 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

3 years ago

Find the surface area of the cylinder give your answer in terms of pi. The radius is 4mm and the height is 5mm

Komok [63]

The surface area of a cylinder is the area of the bases plus the area of the side, or SA = 2*A₁ + A₂

Since the area of a circle is $\pi r^{2}$ ,
SA = 2*( $\pi r^{2}$ ) + A₂

Since the area of the side is height * the circumference of the circle or A₂ = h * $2 \pi r$ , then SA must be;

SA = $2* \pi (r ^{2} )+h*2 \pi r$
SA = $2* \pi (4 ^{2} )+5*2 \pi (4)$
SA = $32* \pi+80 \pi$
SA ≈ 351.858377202

3 0

3 years ago