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lara31 [8.8K]
3 years ago
10

Find the length of . Use that length to find the length of .

Mathematics
2 answers:
Verdich [7]3 years ago
4 0

Answer:

Length of CD is 10.7 cm

Step-by-step explanation:

we are given to find length of CD

Calculation of CD:

Firstly, we will find AC

In triangle ABC, we can use trig

sin(30)=\frac{AC}{10}

AC=10sin(30)

AC=5

now, we can find CD

In triangle ACD , we can use trig

cot(25)=\frac{CD}{AC}

CD=ACcot(25)

now, we can plug AC=5

CD=5cot(25)

CD=10.7

Alex73 [517]3 years ago
3 0

Answer:

AC = 5 cm ,  CD = 10.7 cm.

Step-by-step explanation:

Given : A triangle with a side 10 cm and angle 30 and 25.

To find  : Length of AC and CD.

Solution  We have given that a triangle

By the trigonometric ratio

Sin ( theta) = \frac{opposite}{hypotnuse}.

Sin (30) =  \frac{AC}{10}.

Plug the value of sin (30)

\frac{1}{2} = \frac{AC}{10}.

On multiplying by 10 both sides

Then AC = 5 cm.

By using AC we will find CD

Cot (theta) =  \frac{adjecent}{opposite}.

Cot (25) =  \frac{CD}{5}.

2.144 =   \frac{CD}{5}.

On multiplying both sides by 5

CD = 10.7 cm

Therefore, AC = 5 cm ,  CD = 10.7 cm.

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Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
Two angles are complementary. The measure of ∠ABC is x° and the measure of ∠DBC is (3x + 10)°. What is the value of x?
beks73 [17]
42.5 I think

3x+10+x=180
4x=170
170/4=x
X=42.5
5 0
3 years ago
Read 2 more answers
PLEASE HELP ME I BEG YOU
Rus_ich [418]

You need to find "two-fifths of 30."  Of here means multiplication:

     \begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}

There are 12 athletes in the club.

5 0
3 years ago
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Last year, there were 380 students at woodland middle school. This year, the student population will increase by 5%. What will b
olga_2 [115]
399 because 380 x .05 =19 and 19+380
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5 0
3 years ago
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1. x + 2x - 1 = 38<br> Inverse operation
Lena [83]

Answer:

x=13

Step-by-step explanation:

First, you add the x's together: 2x+x=3x

Now you have:3x-1=38

Add 1 to both sides: 3x=39

1 cancel on the left side of the equation

Divide 3 on both sides: x=39/3

3 cancels on the left side and 39 divided by 3 is 13:

x=13

Hope this helps!

6 0
3 years ago
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