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Oksanka [162]
2 years ago
14

PLEASE HELP ME I BEG YOU

Mathematics
2 answers:
sergiy2304 [10]2 years ago
7 0

Step-by-step explanation:

=(2/5) of 30

=(2/5)×30

=(2×30)/5

=60/5

=12

Rus_ich [418]2 years ago
5 0

You need to find "two-fifths of 30."  Of here means multiplication:

     \begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}

There are 12 athletes in the club.

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I need help with intercepts from a graph
Rina8888 [55]

Explanation: The y axis is the line that goes up and down, vertical. The x axis is the line that goes straight across, horizontal. So, when looking for intercepts we have to see what numbers your graphed line goes through.

Make sure when you are writing your points you write it in (x,y) form. If you don't it will be wrong.

So, for our x intercept it would be -7,0.

This is because your graphed line goes through x at -7 and it has no y, so that would be 0.

For your y intercept, it would be 0,2

This is because our line does not go through x, so we make that 0. It does go through y at 2.

Hope this helps :)

If you need elaboration on anything let me know. I know sometimes with math it is kind of hard to explain through typing.

8 0
3 years ago
362,031,100 km as standard form
Alex777 [14]
300,000,000+60,000,000+2,000,000+31,000+1000+100
6 0
3 years ago
Find the product and simplify.<br> (k+ 4)(-4k – 5)
torisob [31]
The answer is -4k^2 - 21k - 20! so sorry if I’m wrong but it’s the answer I got :>
3 0
3 years ago
Simplify the expression: (3m + 1)(2)
BARSIC [14]

Answer:

6m + 2

Step-by-step explanation:

To simplify the expression you must have to use the distributive property:

(3m + 1)(2)

2 x 3m = 6m

2 x 1 = 2

6m + 2

3 0
3 years ago
Read 2 more answers
Find the critical numbers of the function f(x) = x6(x − 1)5 what does the first derivative test tell you that the second derivat
patriot [66]
The given function is f(x) = x⁶(x-1)⁵

The first derivative is
f'(x) = 6x⁵(x-1)⁵ + 5x⁶(x-1)⁴
       = x⁵(x-1)⁴(6x - 6 + 5x)
       = x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
        = (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
        = (x-1)³(110x⁶ - 120x⁵ + 30x⁴)
        = 10x⁴(x-1)³(11x² - 12x + 3)
The sign of f''(x) at the critical values tell us the nature of the turning point.

f''(0) = 0, therefore a point of inflection exists at x = 0.
f''(6/11) > 0, therefore a local minumum exists at x = 6/11.
f''(1) = 0, therefore a point of inflection exists at x=1.

The graphs shown below confirm these results.

8 0
3 years ago
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