All categories

3 years ago

What three types of auto insurance coverage are the most important to have?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

There are three primary types of coverage offered by the majority of car insurance providers. They include liability, collision, and comprehensive. Each of these has their own ranges of coverage and each may also include extra services.

Step-by-step explanation:

bulgar [2K]3 years ago

7 0

Car insurance: liability, collision, and comprehensive

You might be interested in

7lbs. For 4 people unit rate is

ira [324]

Answer:

Step-by-step explanation:7 ÷4= 4 + 3 ÷ 4 = 30 ÷4 = 2.85

6 0

3 years ago

An account manager for a local software agency believes there is a relationship between the number of contacts and the amount of

amid [387]

Answer:

b is the correct answer

Step-by-step explanation:

hopefully think that it helps you

3 0

3 years ago

Read 2 more answers

3. Sandy's Sweets sells cookies for $1.50 cach while Barbara's Bakery sells cookies for $2.10 each. After

Anna11 [10]

Answer:

5 times

11.50

plz give brainiest

Step-by-step explanation:

4 0

2 years ago

Please help me to answer this

Igoryamba

A. 1 = 3/3 = 4/4 = 52/52 = x/x

B. 5 = 10/2 = 15/3 = 7.5/1.5 = 120/24 = 5a/a

All the ratios must equal each other

5 0

3 years ago

Joe heard from a reliable source that only 22% of people actually sleep 8 hours or more per night. You do a survey and find 58 o

Juliette [100K]

Answer:

95% Confidence interval: (31.32%,47.04%)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 148

Number of people who sleep for 8 hours or longer, x = 58

$\hat{p} = \dfrac{x}{n} = \dfrac{58}{148} = 0.3918$

95% Confidence interval:

$\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting the values, we get:

$0.3918\pm 1.96(\sqrt{\dfrac{0.3918(1-0.3918)}{148}})\\\\ = 0.3918\pm 0.0786\\\\=(0.3132,0.4704)=(31.32\%,47.04\%)$

(31.32%,47.04%) is the required 95% confidence interval.

8 0

3 years ago