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3 years ago

What is the sum? seven-fourths plus negative one-fifth

Mathematics

2 answers:

tangare [24]3 years ago

8 0

Typing it into a calculater using the abc key to make a fraction, it comes out as 1 and 19/20

jok3333 [9.3K]3 years ago

6 0

The answer is 1.55. Did you try finding a common denominator?

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A vendor has 22 balloons for sale: 11 are yellow, 4 are red, and 7 are green. A balloon is selected at random and sold. If the b

jek_recluse [69]

The answer would be C

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4 years ago

What is the volume of the rectangular prism? Round your answer to the nearest Hundredth place if necessary.

pochemuha

Answer:

V = l×w×h units³

Step-by-step explanation:

The volume of a rectangular prism is V = l×w×h

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3 years ago

It's not 3 so what's the volume?

kkurt [141]

The answer is 27. Volume of the cube

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3 years ago

Read 2 more answers

Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Drupady [299]

Answer:

The equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

Let us solve the expression step by step to get the equivalent

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}$

$\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=x^{2\cdot \frac{1}{7}}$

$=x^{\frac{2}{7}}$

also

$\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}$ ∵ $\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}$

$\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=y^{3\cdot \frac{1}{5}}$

$=y^{\frac{3}{5}}$

so the expression becomes

$\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$ ∵ $\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}$

Thus, the equivalent will be:

$\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)$

Therefore, option 'a' is true.

5 0

3 years ago

Find the slope of the line that passes through (-6, -2) and (-7, -2)

Jobisdone [24]

Answer:

$0$

Step-by-step explanation:

We could use the Slope Formula to find the answer, but there's an easier way of doing it. Notice that the y-coordinates of both points are the same. This means that the line that passes through these points is horizontal, which makes our answer $0$ because all horizontal lines have a slope of $0$ .

All horizontal lines have a slope of $0$ because the value of y never changes as the value of x changes, so if we were to input any two points on a horizontal line into the Slope Formula, our numerator would be $0$ (because anything subtracted from itself is $0$ ), leaving us with a result of $0$ regardless of the denominator since $0$ divided by anything is $0$ . Hope this helps!

6 0

3 years ago