Plug them in then solve from left to light
8n-28
4(2n-7)
you cant factor this. There are no powers
Answer:
15.9%
Step-by-step explanation:
Percent decrease formula =
(Initial value - New value/Initial value) × 100
Initial value = 9200kg
New value = 7739.4kg
Percent decrease = (9200 - 7739.4/9200) × 100
Percent decrease = (1460.6/9200) × 100
Percent decrease = 15.8760869565%
Approximately = 15.9%
The percent of decrease in the amount of strawberries used annually is 15.9%
Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
