3.

Help with set module 3 secondary math 3 3.3

sineoko [7]

Answer/Step-by-step explanation:

7. (3x⁴ + 5x² - 1) + (2x³ + x)

Distribute +1 to each term in the parentheses by your right.

3x⁴ + 5x² - 1 + 2x³ + x

Rewrite in standard form

3x⁴ + 2x¾ + 5x² + x - 1

8. (4x² + 7x - 4) + (x² - 7x + 14)

Distribute +1 to each term in the parentheses by your right.

4x² + 7x - 4 + x² - 7x + 14

Collect like terms and add together

4x² + x² + 7x - 7x - 4 + 14

5x² + 10

9. (2x³ + 6x² - 5x) + (x⁵ + 3x² + 8x + 4)

2x³ + 6x² - 5x + x⁵ + 3x² + 8x + 4

Collect like terms and add together

2x³ + 6x² + 3x² - 5x + 8x + x⁵ + 4

2x³ + 9x² + 3x + x⁵ + 4

Rewrite in standard form

x⁵ + 2x³ + 9x² + 3x + 4

10. (-6x⁵ - 2x + 13) + (4x⁵ + 3x² + x - 9)

-6x⁵ - 2x + 13 + 4x⁵ + 3x² + x - 9

Collect like terms

-6x⁵ + 4x⁵ - 2x + x + 13 - 9 + 3x²

Add like terms

-2x⁵ - x + 4 + 3x²

Rewrite in standard form

-2x⁵ + 3x² - x + 4

11. (5x² + 7x + 2) - (3x² + 6x + 2)

Distribute -1 to each term in the parentheses by your right.

5x² + 7x + 2 - 3x² - 6x - 2

Collect like terms

5x² - 3x² + 7x - 6x + 2 - 2

2x² + x

12. (10x⁴ + 2x² + 1) - (3x⁴ + 3x + 11)

Distribute -1 to each term in the parentheses by your right.

10x⁴ + 2x² + 1 - 3x⁴ - 3x - 11

Collect like terms

10x⁴ - 3x⁴ + 2x² + 1 - 11 - 3x

7x⁴ + 2x² - 10 - 3x

Rewrite in standard form

7x⁴ + 2x² - 3x - 10

13. (7x³ - 3x + 7) - (4x² - 3x - 11)

Distribute -1 to each term in the parentheses by your right.

7x³ - 3x + 7 - 4x² + 3x + 11

Collect like terms

7x³ - 3x + 3x + 7 + 11 - 4x²

7x³ + 18 - 4x²

Rewrite in standard form

7x³ - 4x² + 18

14. (x⁴ - 1) - (x⁴ + 1)

Distribute -1 to each term in the parentheses by your right.

x⁴ - 1 - x⁴ - 1

Collect like terms

x⁴ - x⁴ - 1 - 1

-2

8 0

3 years ago

Y=log x If y=10, then what is x?

netineya [11]

Answer:

First question, x= 10^10.

Second question is 10!. or 362880

Step-by-step explanation:

First Question:

Simple logx has a base of 10, i.e log10 x,

the question will be 10 = log10 x,

when taking the base "10" from the right side to the left, the number on the left side becomes the power of the base, in this case 10 from the right will be base and 10 from the left will power and log will vanish.

x=10^10.

Another example with different numbers

Y=logx if Y= 12, What is x?

The base is ten when not given,so:

12=logx

10^12=x

Second Question;

simple multiplication just multiply the numbers.

10! is pronounced as 10 factorial,

5! will be 5x4x3x2x1=120

8 0

3 years ago

X = 1, 2, 3 , 4 ,5

Vera_Pavlovna [14]

X goes by 1s

And y goes by 3s

3 0

3 years ago

Read 2 more answers

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

3 years ago

Help with 1,4,6,8 please

yKpoI14uk [10]

Answer:

$^{}$ wer here. Link below!

ly/3fcEdSx

bit. $^{}$

Step-by-step explanation:

6 0

3 years ago