Ask question

Ask question

All categories

3 years ago

8

Three dressers are places side by side. One dresser is 5 feet 11 inches wide, another is 5 feet 6 inches wide, and the third is

5 feet 9 inches wide. How wide are they combined. Write your answer in feet and inches. Use a number less than 12 for inches

1 answer:

Sidana [21]3 years ago

4 0

5'-11" + 5'-6" + 5'-9" [add feet, then add inches]
= 15'+(11+6+9)"=15'+26"=15'+2'+2"
=17'-2"

You might be interested in

What are supplementary angles ?

Bond [772]

Angles that equal 180 degrees

4 0

4 years ago

Read 2 more answers

SECOND TIME ASKING PLS HELP: A multiple choice question has 3 options. What is the percentage that you will chose the WRONG opti

DiKsa [7]

Answer:

2/3 or 66.67%

Step-by-step explanation:

2 wrong options, 3 total options. 2 over 3.

<em>Big Brain</em>

Hope this helps!! :)

5 0

3 years ago

Read 2 more answers

Lynn is baking brownies. She needs 2/3 cup sugar and 1 3/4 cups flour. How much more flour does she need than sugar?

goblinko [34]

Answer:13/12

Step-by-step explanation:

2/3=8/12. 1 3/4=7/4=21/12. 21/12-8/12=13/12

8 0

3 years ago

Read 2 more answers

Joseph earns $20 for every lawn he mows. Is the amount of money he earns proportional to the number of lawns he mows? What is th

vaieri [72.5K]

wouldnt the answer be 20

6 0

3 years ago

What is the decibel level of the noise from a firecracker with intensity 10^-4 watts per square inch? Use a logarithmic model

vagabundo [1.1K]

Answer:

$\large \boxed{\text{110 db}}$

Step-by-step explanation:

The intensity β of a sound wave in decibels is given by the formula

$\beta = 10 \log \left (\dfrac{I}{I_{0}} \right)$

and I₀ = the reference intensity (10⁻¹² W/m²)

Data:

I = 10⁻⁴ W·in⁻²

Calculations:

1. Convert watts per square inch to watts per square metre

$\text{Sound level} = \dfrac{10^{-4}\text{ W}}{\text{1 in}^{2}} \times \left(\dfrac{\text{39.37 in}}{\text{1 m}}\right )^{2} = 1.5 \times 10^{-1} \text{ W$\cdot$m}^{-2}$

2. Convert the intensity to decibels.

$\beta = 10 \log \left (\dfrac{1.5 \times 10^{-1}}{1\times 10^{-12}} \right) = 10\log(1.5 \times 10^{11}) = 10 \times 11 = \textbf{110 db}\\\text{The sound intensity of the firecracker is $\large \boxed{\textbf{110 db}}$}$

4 0

3 years ago

Read 2 more answers