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3 years ago

Simplify the expression -6(10+9v)

Mathematics

1 answer:

lilavasa [31]3 years ago

6 0

Answer:

-60 - 54v or -60 + (-54v)

Step-by-step explanation:

If you choose to expand this equation to make it easier, you can write it out as (-6 × 10) + (-6 × 9v). With this, you can simplify this to -60 + (-54v).

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3 years ago

SGA is doing a fundraiser to sell candles for project graduation. Small candles cost $4.00 and large candles cost $6.00. They ha

mafiozo [28]

Given:

Cost of small candles = $4.00

Cost of large candles = $6.00

They have at most 50 candles, and want to make at least $100.

To find:

The system of linear inequalities represents the situation.

Solution:

Let x be the number of small candles and y be the number of large candles.

At most 50 candles means total candles must be less than or equal to 50.

$x+y\leq 50$

Want to make at least $100. It means, the total sales must be greater than or equal to $100.

$4x+6y\geq 100$

Therefore, the inequalities in the system of linear inequalities are $x+y\leq 50$ and $4x+6y\geq 100$ .

3 0

2 years ago

What's -3+(0+9) ?? <br> I need to know by tonight

Crank

The answer is 6.
To do this, remember PEMDAS?
You would first have to add what is in the parenthesis THEN do -3 + 9 to get 6.

6 0

3 years ago

Read 2 more answers

A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While

Murljashka [212]

Answer:

The expected number of appearance defects in a new car = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = $\nu$ = $= \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61$ = 0.64

$\sigma^{2}$ = variation of E(X) = $\sum (X - \nu) ^{2}P(X)$ = $(3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61$