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ziro4ka [17]
2 years ago
6

Drag and drop each pair of lines into the correct category to indicate whether the pair of lines are parallel, perpendicular, or

neither.
1/7x + y = 9; y = -7x
y = 3x - 3; 12x - 4y = 12
7y = 2x + 1; 14x + 4y = 12
x - 4y = 18; y = x + 4
3x - 4y = -1; 3y = -4x + 5
Parallel Perpendicular Neither​
Mathematics
1 answer:
ANTONII [103]2 years ago
7 0

Answer:

Step-by-step explanation:

<em>(1).</em> \frac{1}{7} x + y = 9 and y = - 7x <em>( Neither )</em> ; lines intersect.

<em>(2).</em> y = 3x - 3; 12x - 4y = 12 <em>( Neither ) </em>; Lines are overlapped or both equation are of the same line.

<em>(3).</em> 7y = 2x + 1; 14x + 4y = 12 <em>( Perpendicular )</em> ; m_{1} = \frac{2}{7} and m_{2} = - \frac{7}{2} , slopes are opposite reciprocals.

<em>(4).</em> x - 4y = 18; y = x + 4 <em>( Neither )</em> ; lines intersect.

<em>(5).</em> 3x - 4y = - 1; 3y = - 4x + 5 <em>( Perpendicular )</em> ; m_{1} = \frac{3}{4} and m_{2} = - \frac{4}{3} , slopes are opposite reciprocals.

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