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Elenna [48]
2 years ago
7

What elements, found on the right side of the periodic table, usually accept electrons and have a negative valence? A. metals B.

nonmetals C. metalloids D. alkaline metals
Mathematics
1 answer:
krek1111 [17]2 years ago
5 0
<h2>ANSWER:</h2><h3>Non Elements</h3><h3 /><h2>NOTES:</h2><h3>With the exception of HYDROGEN, the elements on the left side of the periodic table are METALS. Elements on the right side of the periodic table are NONMETALS.</h3>
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Which is the correct second step for solving the equation (×+3)^2-4=18
Aleksandr-060686 [28]
(x^2)+9-4=18
x^2+5=18
7 0
3 years ago
Store A sells 12 juice bottles for $4 and store B sells 18 juice bottle for $6. Are the rates equivalent? explain your reasoning
mamaluj [8]

Answer:

Yes!

The rate can be expressed by the ratio 3:1

For every 3 bottles, its $1

For every 6 bottles, its $2

For every 12 bottles its $4

and for every 18 bottles its $6

The juice's are equivalent because the ratio of number to bottles to dollars is equal.

Step-by-step explanation:

7 0
3 years ago
It says use cofunction but still i didnt understand
torisob [31]

Answer:

-\frac{\pi }{22\\}

Step-by-step explanation:

\frac{5\pi }{11}-pi/2

5 0
3 years ago
There is a list of seven numbers. The average of the first four numbers is 5, and the average of the last four numbers is 8. If
sammy [17]

Answer:

6

Step-by-step explanation:

Sum of first 4 numbers= 4*5= 20

This includes 3 + 4th number

Sum of last 4 numbers= 4*8= 32

This includes 4th number + 3

Sum of 7 numbers= 7*(6+4/7)= 46

This includes 3+4th number +3

Number common to both sets= (20+32)- 46 = 6

3 0
3 years ago
A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 101 million kilometers.
Elden [556K]
Kepler's third law described the relation between semi-major axis (or average distance to the star) and the orbital period (how long it takes to complete one lap) as follows: 
                                           a^3 / p^2 = constant
In the case of our Solar system the constant is 1 
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU

Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
3 0
3 years ago
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