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Rina8888 [55]
3 years ago
13

What is the graph of 3x + 5y = –15? Image for option 1 Image for option 2 Image for option 3 Image for option 4

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0
Move x
5y = - 15 - 3x
y = - 3 - 3/5x
y = - 3/5 - 3
-y = 3/5 + 3
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Use the guess and check method <br> 4(x+2)+2=14
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Answer:

1

Step-by-step explanation:

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2 years ago
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Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
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Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

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Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

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2 years ago
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Igoryamba
-10x + 1 + 7x =37

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Answer is x = -18

I think this is the answer
Hope it helps •-•

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The answer is


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