Question

What is the equation of the line that passes through the point (-3,-8) and has a slope of 4?

Answer 1

Step-by-step explanation:

the easiest approach with a given point and the slope of the line is the point-slope form :

y - y1 = a(x - x1)

where "a" is the slope, and (x1, y1) is a point on the line.

so, we get

y - -8 = 4(x - -3)

y + 8 = 4(x + 3)

if we need the slope-intercept form

y = ax + b

we now simplify the point-slope form

y + 8 = 4x + 4×3 = 4x + 12

y = 4x + 4