Step-by-step explanation:
The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.
Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.
What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.
Doing this 125 times, we obtain the number of trials we desire.
For each trial, we get for each child, C:
C1: X + (X or Y)
C2: X + (X or Y)
C3: X + (X or Y)
C4: X + (X or Y)
C5: X + (X or Y)
Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.
I am going to give a few answers:
497,543
504,690
501,991
496,900
Answer:
last one is correct
Step-by-step explanation:
I don't know I think c=23 hope you get it right good luck lol
Distribute the five to [3q-10]
Combine like terms [15q] and [-5q]
Add 50 on each side
Divide by 10 on each side
Simplify
