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3 years ago

Is this a function? A) Yes B) No

Mathematics

2 answers:

Darina [25.2K]3 years ago

8 0

No it’s not a function

Vinil7 [7]3 years ago

6 0

Answer:

no, this is not a function

Step-by-step explanation:

i hope this helps :)

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Yan has four more apples than xavier

ollegr [7]

yan has 4 xavier has zero

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4 years ago

The graph shows the prices of different numbers of bushels of corn at a store in the current year. The table shows the prices of

levacccp [35]

Take any two points

(3,24)
(6,48)

Slope

m=48-24/6-3
m=24/3
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(3,21)
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Difference

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2 years ago

Which expression is equivalent to the given expression? −(2n−6) −2(n−3) −2(n−6) 2n−6 2n + 6

Mice21 [21]

Eek what the heck is that

Step-by-step explanation:

5 0

3 years ago

Given the function h(x), determine the functions which correctly decompose h(x) into component functions f(x) and g(x) so that h

nataly862011 [7]

$\text{Hi there! :)}$

$\large\boxed{g(x) = 7x + 2\text{ , } f(x) = \sqrt{x} - 10}$

$\text{h(x) = f(g(x)), so determine what g(x) was substituted into f(x):}\\\\\text{Given the equation } h(x) = \sqrt{7x +2}- 10:\\\\\text{In the part of the equation with a variable, we see that "7x + 2" is in a square root:}$

$\text{Therefore, we can say that g(x) = 7x + 2:}\\\\\text{If h(x) = f(7x + 2), then f(x) must be:}\\\\f(x) = \sqrt{x} - 10$

$\text{The respective functions would be:}\\\\g(x) = 7x + 2\\\\f(x) = \sqrt{x} - 10$

7 0

3 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$