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3 years ago

Is this a function? A) Yes B) No

Mathematics

2 answers:

Darina [25.2K]3 years ago

8 0

No it’s not a function

Vinil7 [7]3 years ago

6 0

Answer:

no, this is not a function

Step-by-step explanation:

i hope this helps :)

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Lena [83]

A circle is 360°. Since you only have 3 different types of weather, if you split the ° equally, each section would have 120°. The amount of rainy days is 10/30 or exactly 1/3, so 120° are rainy days.

If you do 30 x 12, it equals 360. So that means that each day is 12°. There were 8 cloudy days, so you can do 8 x 12 = 96°

5 0

3 years ago

Zapisz w jak najprostszej postaci: a) -x-4(1-x) b) 3(5x-2)-5(3-4x) c) √2(3-x)-2(1-x√2)

Sonja [21]

Answer:

Step-by-step explanation:

a) -x-4(1-x) =

− 2 x −4 ( 1 − x ) .

2 x − 4

b) 3(5x-2)-5(3-4x) =

3 ⋅ (5 x − 2 ) − 5 ⋅ ( 5 − 4 x )

35 x − 31

c) √2(3-x)-2(1-x√2) =

√ 2 x ⋅ ( 3 −x ) − 2 ⋅( 1 − x √ 2 ) .

2 x √ 2 + 3 √ 2 x -√ 2 x x − 2

4 0

3 years ago

A truck can travel 1200 miles on 80 gallons of gasoline. how far can it travel on 240 gallons of gasoline ? Show your work

pogonyaev

Answer:

3600 miles on 240 gal

Step-by-step explanation:

80 gal can go 1200

160 gal can go 2400

240 gal can go 3600

7 0

2 years ago

Read 2 more answers

Which of the following requires a proof?

zmey [24]

Therorem requires proof.

8 0

3 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: 3 tires are blemished.

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: 2 tires are blemished.

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: 1 tires are blemished.

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: No tires are blemished.

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

3 years ago