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LenaWriter [7]
3 years ago
9

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Ans: the numbers are: 4,6 and 8.

Let the three consecutive positive even integers be n, n+2, and n+4

According to the given problem, The sum of squares of three consecutive positive even integers  is 116

Therefore, check the image for the factorization part:

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Solve the rational equation 1/n-4 - 2/n = 3/4-n
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Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

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\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

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