All categories

3 years ago

What is the Answer for X/3+11=16

Mathematics

1 answer:

lidiya [134]3 years ago

5 0

The answer would be nine

You might be interested in

Please help 15 points

Gre4nikov [31]

Answer:

i really don’t know ,

sorry , I’m so sorry

7 0

3 years ago

For which value of x is the equation 3x + x = 2x + 24 true?

Lynna [10]

Answer:

D) 12

Step-by-step explanation:

3x+x=2x+24

4x=2x+24

4x-2x=24

2x=24

x=24/2

x=12

4 0

3 years ago

A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.

mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

Center of the circle:

The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)$

$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

$r = \sqrt{1^2}$

$r = 1$

Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

here, (a,b) are the center points of the circle

in our case this is $(a,b)=(x_m,y_m)=(7,5)$

and r = 1

$(x-7)^2+(y-5)^2=1^2$

$(x-7)^2+(y-5)^2=1$

This is the equation of the circle!

3 0

3 years ago

Write the expression in complete factored form. (X + 8) - 9(X + 8) =

Irina-Kira [14]

Answer:

Step-by-step explanation:

Do the brackets first

X+8= 8x

then you plus 8x + 8x =16x

16x -9 =7x

4 0

3 years ago

How is this answer D?

kompoz [17]

It's a equilateral triangle with each side being equal to the radius.

So the area is $\dfrac{8^2\sqrt 3}{4}=\dfrac{64\sqrt3}{4}=16\sqrt3$

7 0

3 years ago