The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
The picture is unclear so I cannot really help. I'm sure I could if it was clearer though.
Answer:
Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.
h(x) = f(x) + g(x)h(x)=f(x)+g(x) h(x) = f(x) - g(x)h(x)=f(x)−g(x)
h(x) = \frac{f(x)}{g(x)}h(x)=
g(x)
f(x)
h(x) = f(g(x))h(x)=f(g(x))
And many more.
The approach or formula to use depends on the question.
In this case, the combined function is:
f(x) = 75+ 10xf(x)=75+10x
The savings function is given as
s(x) = 85s(x)=85
The allowance function is given as:
a(x) = 10(x - 1)a(x)=10(x−1)
The new function that combined his savings and his allowances is calculated as:
f(x) = s(x) + a(x)f(x)=s(x)+a(x)
Substitute values for s(x) and a(x)
f(x) = 85 + 10(x - 1)f(x)=85+10(x−1)
Open bracket
f(x) = 85 + 10x - 10f(x)=85+10x−10
Collect like terms
mark as brainiest
f(x) = 85 - 10+ 10xf(x)=85−10+10x
f(x) = 75+ 10xf(x)=75+10x
Answer:
Step-by-step explanation:
5p + 2(p + 4) .......because pencil cases (p) sell for 5 bucks a piece....and mechanical pencils (p + 4), sell for 2 bucks a piece. She is basically selling 4 more mechanical pencils then she is pencil cases.
Answer:
30% chance the reason I say that is because he only has 1 kiwi and for the most part he would choose the Kiwi first don't quote me on that just trying to help
