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3 years ago

Can anyone show me how I would figure this problem out

Mathematics

2 answers:

jeka57 [31]3 years ago

5 0

The value of x is the number inside the parenthesis, so h(-4) gives x a value of -4.

The equation says when X is ≤ -4 use the first equation

So h(-4) = -1/2(x) -15

= -1/2(-4) -15

= 2 -15

= -13

When x = -2 (h(-2) ) use the 2nd equation:

h(-2) = 20-3x^2

=20-3(-2)^2

= 20-3(4)

=20-12

Now you have -13 + 3(8)

= -13 + 24

=11

The answer should be 11

kvv77 [185]3 years ago

3 0

Answer:

Step-by-step explanation:

it means if x =< -4 do

h(x) = - 0.5x - 15

else if x > -4 do

h(x) = 20 - 3x^2

so from the question we need to find the value of h(-4) + 3h(-2)

h(-4) + 3h(-2) = ( - 0.5 * ( -4 ) - 15 ) + 3( 20 - 3( -2 )^2 )

= ( -13 ) + 24 = 11

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60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2

abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
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Plug in the x-coordinate "t" that was given for any point.

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We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
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So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.

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