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Jlenok [28]
3 years ago
5

Can anyone show me how I would figure this problem out

Mathematics
2 answers:
jeka57 [31]3 years ago
5 0

The value of x is the number inside the parenthesis, so h(-4) gives x a value of -4.

The equation says when X is ≤ -4 use the first equation


So h(-4) = -1/2(x) -15

= -1/2(-4) -15

= 2 -15

= -13


When x = -2 (h(-2) ) use the 2nd equation:

h(-2) = 20-3x^2

=20-3(-2)^2

= 20-3(4)

=20-12

=8


Now you have -13 + 3(8)

= -13 + 24

=11


The answer should be 11

kvv77 [185]3 years ago
3 0

Answer:

11

Step-by-step explanation:

it means if  x =< -4 do

h(x) = - 0.5x - 15

else if x > -4 do

h(x) = 20 - 3x^2

so from the question we need to find the value of h(-4) + 3h(-2)


h(-4) + 3h(-2) = ( - 0.5 * ( -4 ) - 15 ) + 3( 20 - 3( -2 )^2 )

= ( -13 ) + 24 = 11

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The solutions to the given quadratic equation {49n² - 301n + 42 = 0 } are 1/7 and 6.

<h3>What are the solutions to the given quadratic equation?</h3>

Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is expressed as;

ax² + bx + c = 0

Where x is the unknown

To solve for x, we use the quadratic formula

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Given the equation in the question;

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We plug in these values into the quadratic formula.

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x = (-(-301) ±√((-301)² - 4 × 49 × 42 )) / (2 × 49)

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Learn more about quadratic equations here: brainly.com/question/1863222

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