The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Oh u got oddseyware lol i hat that wish i could help u dont have the suggestions bro
Answer:
See below
Step-by-step explanation:
x(x-2y)-(y-x)2
Final result :
-y2
Step by step solution :
Step 1 :
Equation at the end of step 1 :
x • (x - 2y) - (y - x)2
Step 2 :
2.1 Evaluate : (y-x)2 = y2-2xy+x2
Final result :
-y2
Answer:
Ordered pairs are ( -3, 0) (0, 3)
Step-by-step explanation:
Now when your graphing, go up 3 spots in the y-axis ( up & down) and plot your point now do the same for your x-axis (( left and right), so go over to the left 3 places, and there now connect the 2 points and your done. Hope that helps!