Start by graphing each line.
• Because the first inequality is smaller than, it will have a dotted (- - -) line.
• Because the second inequality is smaller than or equal to, it will have a solid line (---).
Then, plug in points to see where your shading will go. If the statement is true (x = x), you will shade that area along the line.
0 is less than 2.
Do the same step for the other equation. Your solution to the problem is any point that lies between the shading from both inequalities (where the blue and red meet).
Answer:
If I've done it right the answer should be A, the figures are congruent because a 270 rotation about the origin a d a reflection of the x-axis
Answer:
Option b is correct 175
Step-by-step explanation:
n = 7
k = 6
3k -2 ------1
put k = 6 in above eq. for finding first term
a1 = 3(6) - 2 = 18 - 2 = 16
put k = 7 in above eq. for finding first term
a2 = 3(7) - 2 = 21 - 2 = 19
a3 = 3 (8) - 2 = 24 - 2 = 22
16, 19 , 22, ... //Arithmetic series formation
a1 = 16 , a2 = 19
d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms
Using sum forumula for arithmetic series
sum = 
= 
= 
= 
= 
= 7 * 25
= 175
The effect of Claudia's changing the height of of the triangle from 1 inch
to 3 inches is the option;
- The height of the triangle changed to three inches but the width remained 1 inch
<h3>Which option gives the effect of changing the height?</h3>
The given dimensions of the equilateral triangle Claudia added are;
Height of the triangle = 1 inch
Width of the triangle = 1 inch
The value Claudia typed in the Shape Height box = 3
Required:
What happened to the shape after she press Enter
Solution:
By entering 3 in the Shape Height box, changes the height of the
equilateral triangle to 3 inches but the width remains 1 inches
From a similar question posted online, the correct option is therefore;
- The height of the triangle changed to three inches but the width remained 1 inch
Learn more about triangles here:
brainly.com/question/16430835
Solution
The range is defined as:
Range = Max - Min
For this case we can conclude that the best solution would be:
B, C
