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Alborosie
3 years ago
15

Find a101 of the sequence 5,8,11,

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

305

Step-by-step explanation:

This sequence es the sum of 3

5+3 =8

8+3 = 11

then

101 = 100 + 1

the fisrt date is 5

the another 100:

100*3 = 300

300 + 5 = 305

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Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
What is 5/9 rounded to the nearest half
mash [69]

Answer:

1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the midpoint of A and B where A has coordinates (2, 4)<br> and B has coordinates (-3, -9).
tatuchka [14]

Answer:

(-0.5,-2.5)

Step-by-step explanation:

  • (x1 + x2) / 2 = x midpoint
  • (y1 + y2) / 2 = y midpoint
<h3>X:</h3>

⇒ 2 + -3 = 5

⇒ 5 / 2 = -0.5

<h3>Y:</h3>

⇒ 4 + -9 = -5

⇒ -5 / 2 = -2.5

→ = (-0.5, -2.5)

4 0
2 years ago
Read 2 more answers
Consider the ratio 3:5. Can you create an equivalent ratio by adding the same number to each quantity in the ratio? Explain
iragen [17]
Yes because the unit rate would be 1:2 and that's the rate of change in which 3:5 has.
HOPE IT HELPS!!
4 0
3 years ago
Read 2 more answers
Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y &lt; 12 8x -3y &g
liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

10x + 4y < 12

8x - 3y > 20

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

10x + 4y < 12

10 * 3 + 4 * -8 < 12

30 - 32 < 12

-2 < 12 --- True

8x - 3y > 20

8 * 3 - 3 * -8> 20

24 +24> 20

48> 20 --- True

(2, 5)

x = 2 and y = 5

10x + 4y < 12

10 * 2 + 4 * 5 < 12

20 + 20 < 12

40 < 12 --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

10x + 4y < 12

10 * -5 + 4 * 1 < 12

-46 < 12 --- True

8x - 3y > 20

8 * -5 - 3 * 1 > 20

-43 > 20 --- False

(10, 3)

x = 10 and y = 3

10x + 4y < 12

10 * 10 + 4 * 3 < 12

112 < 12 --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

10x + 4y < 12

10 * 2 + 4 * -10 < 12

-20 < 12 --- True

8x - 3y > 20

8 * 2 - 3 * -10 > 20

46 > 20 --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

4 0
2 years ago
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