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makvit [3.9K]
3 years ago
9

Two motorcycles are traveling at speeds of 120 kilometers per hour and 90 kilometers per hour respectively. If the faster one tr

avels for 4 hours longer than the slower one and also goes twice as far, how far did the slow one travel?
Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0
<span>T is the time traveled by the slower one
(120km/hr)(T+4hrs)=2(90km/hr)(T)
120T+480=180T
480=(60T)
8=T
The slow one traveled 8 hours.

(8hrs)(90km/hr)=720km
ANSWER: The slower bike traveled 720 km
.
CHECK:
(120km/hr)(T+4hrs)=2(90km/hr)(T)
(120km/hr)(8hrs+4hrs)=2(90km/hr)(8hrs)
1440km=2(720km)
1440km=1440km</span>
dlinn [17]3 years ago
4 0

Answer:

Can someone help

Step-by-step explanation:

plz

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