Question

This line has a slope of -3 and passes through the point (4, -10)

Answer 1

Answer:

Step-by-step explanation:

y= mx+c

-10= -3 x 4 +c

-10= -12 +c

c= 2

then, y= -3x+2 would be the answer, if you were wanting the equation of the line.

Answer 2

Answer:

y+10=-3(x-4)

Step-by-step explanation:

to understand this

you need to know about:

• linear equation i.g point-slope form
• PEMDAS

given:

slope or m=-3

(x1,y1)=(4,-10)

to find:

point-slope form of linear equation

let's solve:

point-slope form of a linear equation is

y-y1=m(x-x1)

$first \: step \colon \: \\ substitute \: the \: given \: values \: of \: m \: and \: (x,y) = (4,- 10)$

$y - ( - 10) = - 3(x - (4))$

$last \: step \colon \: simplify$

$y + 10 = - 3(x - 4)$