The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
Let x = length of base and leg
The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base
P = b₁ + b₂ + 2(leg)
28 = 3x + 5x + 2(x)
28 = 8x + 2x
28/10 = 10x/10
2.8 = x
Now, substitute the values:
P = b₁ + b₂ + 2(leg)
28 = 3(2.8) + 5(2.8) + 2(2.8)
28 = 8.4 + 14 + 5.6
28 = 28
Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches
Answer:
24x^2 - 12x
Step-by-step explanation:
C=4x -2
D=x + 5x
(4x - 2) * (x +5x)
4x^2 + 20x^2 - 2x - 10x
=24x^2 - 12x
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
Answer:
m=76
Step-by-step explanation:
5 + 6 hahahahaha hahhahhahaha
