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Alex_Xolod [135]
3 years ago
15

Please help with this q

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

\frac{2 {x}^{2} - 2x }{x - 1}  \div  \frac{2x + 8}{x - 3}  \\  =  \frac{2x {}^{2}  - 2x}{x - 1}  \times  \frac{x - 3}{2x + 8} \\  =  \frac{(2 {x}^{2} - 2x)(x - 3) }{(x - 1)(2x + 8)}

So:

1) x - 1 ≠ 0

x ≠ 1

2) 2x + 8 ≠ 0

2x ≠ -8

x ≠ -4

(B)

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8 0
3 years ago
The mean of a set of 5 numbers is 12. One of the numbers in the set is 16. If 16 is removed from the list, what is the new mean?
Reil [10]

The new mean is 11

Step-by-step explanation:

The mean = sum of the numbers ÷ numbers

  • The mean of a set of 5 numbers is 12
  • One of the number is 16
  • We need to find the new mean if 16 is removed from the set of numbers

∵ The set has 5 numbers

∵ The mean of the 5 numbers is 12

- Substitute these values in the rule of the mean above

∴ 12 = sum of the numbers ÷ 5

- Multiply both sides by 5

∴ 60 = sum of the numbers

∵ One of the number is 16

∵ 16 is removed from the set of the number

- Subtract 16 from the sum and the numbers will be four numbers

∵ The new sum = 60 - 16

∴ The new sum = 44

∵ The set has 4 numbers

∴ The new mean = 44 ÷ 4 = 11

The new mean is 11

Learn more:

You can learn more about the mean in brainly.com/question/5069437

#LearnwithBrainly

6 0
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$250, 2.85%, 3 years Simple interest
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What equals 60 36 and 48
Deffense [45]
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