The given expression becomes undefined when y=5 or y = -3. The answer is option D.
Step-by-step explanation:
The value of the given expression becomes undefined when the denominator equals 0.
Hence to find the value of y which makes the expression undefined, we can equate the value of the denominator to zero and solve it .
Step 1
Equate the denominator to 0.
y^{2} - 2y -15 = 0
Step 2
Solve the above equation to get the value of y.
y^{2} - 2y -15 = 0
=> (y-5)(y+3) =0 [ Roots of the quadratic equation]
=> y = 5 or y = -3.
Hence when y = 5 or y = -3 the denominator becomes 0, which makes the expression (2y+7)/0 and hence it is undefined.
a. Let 
be a random variable representing the weight of a ball bearing selected at random. We're told that 
, so
where 
. This probability is approximately
b. Let 
be a random variable representing the weight of the 
-th ball that is selected, and let 
be the mean of these 4 weights,
The sum of normally distributed random variables is a random variable that also follows a normal distribution,
so that
Then
c. Same as (b).
I believe the 3rd answer down if the information you provided is correct
Squaring the sum on the top, rules out 1 and 2 (not squaring the 7 only)
then 4 times the difference. so I believe 4 (x-1) on the bottom.
Answer:
20
Step-by-step explanation:
this is non linear because the rate of change is not constant.
3rd answer
